Quote:
Originally Posted by Jerry Clayton
Pi x R squared equals the piston area for fiquring the lifting pressure -------example--------a 4 inch bore size would be R = 2------ soooo 2 x2 x 3.14 = 1256 x 100 psi = 125600 lbs total force------
The aluminum heads -the washers under the nuts have squeased the alum head material into the threaded area of the stud which will keep the head tight against the block----There are step washers available that do require clearancing but will prevent that------
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Uh, that would be 12.56 in², not 1,256 - so 1,256 lbs. force @ 100 PSI.
460 CID standard bore is 4.36", so (4.36 ÷ 2)² x 3.14159 = 4.7524 x 3.14159 = 14.93 in² x 100 PSI = 1,493 lbs.
My earlier numbers were incorrect.