Quote:
Originally posted by Clois Harlan
Given this formula does that mean that a Red Holley (97 gph at 7 psi) is only capable of managing a 303 hp engine?
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97 gph = 630.5 lbs per hour. (6.5 lbs per gallon x 97 = 630.5)
.5 lbs per hour per HP = 1261 hp. (630.5 lbs / .5 = 1261.) or conversely (630.5 lbs x 2 }= 1261 hp. {.5 lbs = 1 hp, therefore 1 lb = 2 hp}
The formula is the standard used by the SAE. Also it is the standard formula used by every race engine developer in the known world. (Well, some use liters per hour per kilowatt, but the equation is the same.)
Note: Look at any dyno chart and you will see reference fuel burn in lbs per hour per HP. It always is in the .35>.50 lbs per hp range. (Unless the tune is WAY OFF!!!!)