[trularin]

Okay, the 8" cleaner probably will not flow the air you need.

I copied this formula from K&N:
Use the formula below to compute the minimum size filter required for your particular application. The usable portion of the filter is called the EFFECTIVE FILTERING AREA which is determined by multiplying the diameter of the filter times Pi (3.1416) times the height of the air filter in inches, then subtracting .75-inch. We subtract .75-inch to compensate for the rubber seals on each end of the element and the filter material near them since very little air flows through this area.

A= (CID x RPM)/20839


A = effective filtering area
CID = cubic inch displacement
RPM = revolutions per minute at maximum power

Example: A 350 CID Chevy engine with a horsepower peak at 5,500 rpm.

A= ( 350 x 5500 )/20839 = 92.4 Square Inches

If you are sizing a panel filter, multiply the width of the filter area (not the rubber seal) times its length. If you are sizing a round filter, use the following formula to determine the height of the filter.

H= (A/(d * 3.14159) ) + .75


A = effective filtering area
H = height
D = outside diameter of the filter
3.14 = pi
0.75 = the rubber end caps

I think you will find the air cleaner may only be good for 2000 to 2500.

Check your timing. I am not sure about your FI 302, but most engines that are built have a 32 to 38 degree total advance and an initial that will give them that. You may want to search "timing" on the site for more info.

If you have a fuel pressure guage, you can see if the rail gets depleted as you step on it. Say at idle you are running 35 to 40 pounds to the injectors. You nail it and as it climbs in RPM the fule pressure drops to 10 pounds. You will have miss fires and a complete loss of power.

Well, GTG. Keep us posted on what you find. Hope this helps.