Lets say we've got dual masters so half the force goes to the front master 300 lbs. P = F/A = 300/.441" = 680 lbs/sq in. Lets use this master on a 4 piston Wilwood with 1.75" pistons. 2(pistons per side) x Pi x Rad sq = 2 x 3.14 x 1.75/2 sq = 4.808 in sq. Force = Press x Area = 680 x 4.808 = 3269.44 lbs per side or 6538.8 for the front. If you calculate the rears out the same way putting your numbers in of course you'll have a total number on your stopping force. The difference between them is the brake bias. You want at least 60% of your braking on the front wheels. Check my maths and throw in the center of gravity, weight, coefficient of friction on the pad material and a few other things and you'll have some good theory to put into practice. There's a good chart here that calcs for you if you put your numbers in.
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