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01-12-2014, 06:30 PM
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CC Member
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Join Date: Aug 2000
Location: Glendale,
AZ
Cobra Make, Engine: SPF 468ci 550HP + 150HP NX Matching Shelby GT500 650HP
Posts: 4,227
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You need distance from B to C and A to C. You have created a triangle from a straight line. Correction of B to line up between A and C would be trigonometry based. Answer would obviously be slightly less than 1/8 inch in same left direction you moved A.
Or you could just blame Bush.
AZ Bob
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AZCOBRA, AZBOBS Plates & JAFMO
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01-12-2014, 06:32 PM
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Half-Ass Member
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Join Date: Jun 2005
Cobra Make, Engine: ERA #732, 428FE (447 CID), TKO600, Solid Flat Tappet Cam, Tons of Aluminum
Posts: 22,000
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Quote:
Originally Posted by Bernica
Did not pick up on parallel lines anywhere. Only one line. You got dat double vision goin' again Patrick?
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Here is Mikiec's triangle; it's trickier than you might think and he's just having fun with you. During the off-season, he's guest lecturer at M.I.T. on this stuff....
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01-12-2014, 06:51 PM
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Senior CC Premier Member
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Join Date: Nov 2004
Location: SoCal,
CA
Cobra Make, Engine: CSX #4xxx with CSX 482; David Kee Toploader
Posts: 3,574
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This is why I have been looking for someone to explain compound curves in "carpenter terms". If he is at MIT, then he know Catia and beyond. Back to my tape measure.
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All that's stopping you now Son, is blind-raging fear.......
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01-12-2014, 06:56 PM
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Senior Club Cobra Member
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Join Date: May 2007
Location: Mesa,
AZ
Cobra Make, Engine: Contemporary Classic, 428 FE CCX 3069
Posts: 7,506
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Patrick,who are you trying to fool? Mikie can't. even spell.MIT!
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Dan in Arizona
CCX3209
"It's a great car and I love it, but it doesn't do 'SLOW' very well."
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01-13-2014, 05:52 AM
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Senior Club Cobra Member
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Join Date: Jun 2000
Location: Gilford,
NH
Cobra Make, Engine: FFR 302 carb
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Actually, I did take a couple of classes at MIT.
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01-13-2014, 06:05 AM
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Senior Club Cobra Member
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Join Date: May 2007
Location: Mesa,
AZ
Cobra Make, Engine: Contemporary Classic, 428 FE CCX 3069
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Oops. I guess I was wrong. He can spell MIT.
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Dan in Arizona
CCX3209
"It's a great car and I love it, but it doesn't do 'SLOW' very well."
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01-13-2014, 06:55 AM
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CC Member
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Join Date: Apr 2009
Location: Phoenix,
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Now that we are done playing, the answer should be obvious. The answer is you don't have to move squat. You can always draw a straight line between two points no matter where you place them. Mikie does not put any qualifications on this line.
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01-13-2014, 08:24 AM
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Senior ClubCobra Member
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Join Date: Feb 2006
Location: Northern,
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Cobra Make, Engine: LA Exotics
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You're assuming that the line is running left to right. What if it is running up and down?
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01-13-2014, 09:47 AM
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The question was very simple. " How much do I have to move point B to maintain a straight line to point C?".
Mikie has sucked us all into thinking it is complicated, when it is truly not.
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Last edited by Car Nut; 01-13-2014 at 09:50 AM..
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01-13-2014, 10:28 AM
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Senior Club Cobra Member
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Join Date: May 2007
Location: Mesa,
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Cobra Make, Engine: Contemporary Classic, 428 FE CCX 3069
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Did you see my question about adjusting iron sights. That sounds like an adjusting iron sights question. In which case it does matter how far it is from A - C and how far it is from A - B.
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Dan in Arizona
CCX3209
"It's a great car and I love it, but it doesn't do 'SLOW' very well."
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01-13-2014, 10:43 AM
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Senior CC Premier Member
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Join Date: Nov 2004
Location: SoCal,
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Quote:
Originally Posted by mikiec
Point A to Point B = 26 inches. Point C is a fixed point in the distance.
If I move point A 1/8" to the left. How much do I have to move point B to maintain a straight line to point C?
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As said above, there is always a straight line between only two points. As put my Mikie, the question is about moving B to maintain a straight line to C, which would tell me that he is only asking about these two points. He does not say "through C", he says "to C". If that is true, then it doesn't matter where A gets moved to. Just taking a shot!
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All that's stopping you now Son, is blind-raging fear.......
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01-13-2014, 10:57 AM
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CC Member
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Quote:
Originally Posted by Bernica
As said above, there is always a straight line between only two points. As put my Mikie, the question is about moving B to maintain a straight line to C, which would tell me that he is only asking about these two points. He does not say "through C", he says "to C". If that is true, then it doesn't matter where A gets moved to. Just taking a shot!
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Agreed.
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01-13-2014, 11:02 AM
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Quote:
Originally Posted by Danr55
Did you see my question about adjusting iron sights. That sounds like an adjusting iron sights question. In which case it does matter how far it is from A - C and how far it is from A - B.
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Where do you see anything at all in his question that substantiates that. You are overthinking and making assumptions the text does not give you.
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01-13-2014, 11:52 AM
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Dan, I know how to adjust iron sights.
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01-13-2014, 11:56 AM
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Senior Club Cobra Member
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OK,
Let's change this a little bit. Point C does not move. I'll give it a distance say 10 feet. Ig point A is moved 1/8 inch how much does point B need to move to keep the straight line?
Professor Erwin Corey asked this.
Mike
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01-13-2014, 12:10 PM
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Senior Club Cobra Member
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Join Date: May 2007
Location: Mesa,
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Cobra Make, Engine: Contemporary Classic, 428 FE CCX 3069
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Point B will move .10274 inches in the same direction as A.
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Dan in Arizona
CCX3209
"It's a great car and I love it, but it doesn't do 'SLOW' very well."
Last edited by Danr55; 01-20-2014 at 12:49 PM..
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01-13-2014, 12:14 PM
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Senior CC Premier Member
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Join Date: Nov 2004
Location: SoCal,
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Cobra Make, Engine: CSX #4xxx with CSX 482; David Kee Toploader
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Quote:
Originally Posted by mikiec
OK,
Let's change this a little bit. Point C does not move. I'll give it a distance say 10 feet. Ig point A is moved 1/8 inch how much does point B need to move to keep the straight line?
Professor Erwin Corey asked this.
Mike
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Still not clear. Changing from 26" to 10 feet? I don't think that matters. And, you also don't state if you are solving the straight line "to" C or "through" C from A to B. Otherwise, sounds like my previous answer would stand.
Assumptions:
A to B are a straight line (doesn't matter how far apart)
C is somewhere in space (no statement that it resides in the same straight AB line, only in a fixed point, which could be miles away!)
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All that's stopping you now Son, is blind-raging fear.......
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01-13-2014, 12:57 PM
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Senior Club Cobra Member
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Join Date: May 2007
Location: Mesa,
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Bernie, Try with ABC being a straight line. A being moved out of line 1/8" creating lines AC and BC. The issue is to solve for the distance from point B to line AC as the short leg of a triangle.
Line ABC=120"
Line AB = 26"
Line BC = 94"
Point A moves in an arc with Point C at the center, .125"
Solve for the distance from B to line AC.
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Dan in Arizona
CCX3209
"It's a great car and I love it, but it doesn't do 'SLOW' very well."
Last edited by Danr55; 01-13-2014 at 01:03 PM..
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01-13-2014, 01:23 PM
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Half-Ass Member
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Join Date: Jun 2005
Cobra Make, Engine: ERA #732, 428FE (447 CID), TKO600, Solid Flat Tappet Cam, Tons of Aluminum
Posts: 22,000
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Quote:
Originally Posted by Danr55
Bernie, Try with ABC being a straight line. A being moved out of line 1/8" creating lines AC and BC. The issue is to solve for the distance from point B to line AC as the short leg of a triangle.
Line ABC=120"
Line AB = 26"
Line BC = 94"
Point A moves in an arc with Point C at the center, .125"
Solve for the distance from B to line AC.
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Dang Dan, give 'em a hint. Tell them that the shortest distance from point B to line AC will be a line that is perpendicular to AC. Now you've got a right triangle with this newly created line being the side you're trying to solve. AB is the hypotenuse. Now that's a pretty good hint.
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01-13-2014, 02:15 PM
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CC Member
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Rlmao
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