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01-12-2014, 09:39 AM
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Senior Club Cobra Member
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Join Date: Jun 2000
Location: Gilford,
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Cobra Make, Engine: FFR 302 carb
Posts: 8,121
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Wacko qusetion
Point A to Point B = 26 inches. Point C is a fixed point in the distance.
If I move point A 1/8" to the left. How much do I have to move point B to maintain a straight line to point C?
Last edited by mikiec; 01-12-2014 at 09:42 AM..
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01-12-2014, 09:55 AM
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CC Member
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Join Date: Mar 2006
Location: San Marcos california,
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Cobra Make, Engine: 1989 KCC from South Africa Right Hand Drive
Posts: 1,601
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??????
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01-12-2014, 10:47 AM
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CC Member
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Join Date: Jan 2005
Location: Hillsboro,
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Cobra Make, Engine: Scratch built CSX style frame, Carbon fiber body, 393 Stroker, T-bird IRS, T5
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If A, B, and C are in a straight line to begin with, the amount of movement of point C would equal 1/8" x the ratio of the distances between AB and BC (AB/BC=???? x 1/8")
Bob
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01-12-2014, 10:54 AM
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Senior CC Premier Member
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Join Date: Nov 2004
Location: SoCal,
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Cobra Make, Engine: CSX #4xxx with CSX 482; David Kee Toploader
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If A to B was a straight line in the first place, and C is in that straight line, you don't move anything. You still have a straight line. Unless I'm missing something or you are trying to make C equadistant between A and B. Sunday mornings are tough for math class! 
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All that's stopping you now Son, is blind-raging fear.......
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01-12-2014, 11:04 AM
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CC Member
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Join Date: May 2006
Location: St. Louisville,
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Cobra Make, Engine: A&C 67 427 cobra SB
Posts: 2,445
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Quote:
Originally Posted by mikiec
How much do I have to move point B to maintain a straight line to point C?
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This question is worded very poorly. It is not clear if the straight line is from point B to point C, but I assume so.
This is a trick question. You can always draw a straight line between any two points, so you do not need to move point B. Furthermore you can move point B anyplace in the universe and still draw a straight line to point C.
If the question is to get a straight line from point A to point B with point C fixed, after point A was moved, then the previous answer is correct, if you move point B to the right. |
01-12-2014, 11:28 AM
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Senior Club Cobra Member
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Join Date: May 2007
Location: Mesa,
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Cobra Make, Engine: Contemporary Classic, 428 FE CCX 3069
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If A B C is a triangle, you don't have to move B at all. It is already in line with C. If A B C is a straight line, you essentially create a triangle when you move A so you would solve for the height of the triangle which would be the distance from point B to line AC. That would depend on the distance from A to C. Really need more information regarding the preliminary relationship between A B and C. If they are a straight line, it would help to know either the distance AC or BC to have a real solution. It almost sounds like we are adjusting iron sights..
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Dan in Arizona
CCX3209
"It's a great car and I love it, but it doesn't do 'SLOW' very well."
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01-12-2014, 11:52 AM
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CC Member
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Join Date: Apr 2009
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Since C is a fixed point and the distance from AC and BC is constant. Then AB is also wants to remain constant along an arc with C being the center point. To keep AB constant you need to move it the same distance along the line of the formed arc. In the end, it doesn't matter, you can always draw a straight line if you're sober enough.
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Last edited by Car Nut; 01-12-2014 at 12:00 PM..
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01-12-2014, 11:55 AM
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Senior CC Premier Member
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Join Date: Nov 2004
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Quote:
Originally Posted by Danr55
If A B C is a triangle, you don't have to move B at all. It is already in line with C. If A B C is a straight line, you essentially create a triangle when you move A so you would solve for the height of the triangle which would be the distance from point B to line AC. That would depend on the distance from A to C. Really need more information regarding the preliminary relationship between A B and C. If they are a straight line, it would help to know either the distance AC or BC to have a real solution. It almost sounds like we are adjusting iron sights..
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Agree on the triangle theory, if that's what he is asking. Not clear. Trying to solve dead-center on a circle between AB?
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All that's stopping you now Son, is blind-raging fear.......
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01-12-2014, 11:56 AM
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CC Member
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Join Date: Jun 2001
Location: Mesa,
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Cobra Make, Engine: ERA #2119 289FIA
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"Wacko qusetion"
Yes, it is a Waco QUSETION.
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Karlos
"In the Land of the Pigs, The Butcher is King"
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01-12-2014, 01:35 PM
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Senior Club Cobra Member
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Join Date: Jun 2000
Location: Gilford,
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My bad. A B C are in a straight line.
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01-12-2014, 02:03 PM
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CC Member
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Join Date: Mar 2003
Location: Wickenburg AZ- PHX, Cinci, Indy before,
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You would have to see it in order to know what is in it? Just like the OB Care. My answer is leave C along. Sounds like C is on the way to B or C is on the way to A. It doesn't make any difference. Are we all bored today?
Here I sit trying to give away a 110" X 36" one piece mirror? Along with answering a high school math sophomore test question... 
Last edited by Fitz; 01-12-2014 at 02:09 PM..
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01-12-2014, 04:04 PM
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Senior CC Premier Member
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Join Date: Nov 2004
Location: SoCal,
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Don't forget to finish taking down the Christmas lights!
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All that's stopping you now Son, is blind-raging fear.......
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01-12-2014, 04:08 PM
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Half-Ass Member
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Join Date: Jun 2005
Cobra Make, Engine: ERA #732, 428FE (447 CID), TKO600, Solid Flat Tappet Cam, Tons of Aluminum
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OK, so all three points sit on a hyperbolic paraboloid, right?  |
01-12-2014, 04:54 PM
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Senior CC Premier Member
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There's always Catia software if you are burning for an answer. Measures all points in space. When you're finished, you can design an airplane or the Disney Concert Hall! I'll just stick to a tape measure and calculator
https://www.youtube.com/watch?v=e04CjtjZ8lk
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All that's stopping you now Son, is blind-raging fear.......
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01-12-2014, 05:00 PM
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Half-Ass Member
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Join Date: Jun 2005
Cobra Make, Engine: ERA #732, 428FE (447 CID), TKO600, Solid Flat Tappet Cam, Tons of Aluminum
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Quote:
Originally Posted by Bernica
There's always Catia software if you are burning for an answer. Measures all points in space. When you're finished, you can design an airplane or the Disney Concert Hall! I'll just stick to a tape measure and calculator |
I've been trying to teach Chas non-Euclidean Geometry for years, but, man, he is a slowwww learner. I got him Mathematica for Christmas -- I'm hoping that will help. |
01-12-2014, 05:03 PM
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CC Member
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Quote:
Originally Posted by mikiec
My bad. A B C are in a straight line.
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Sounds like you need to go straight to your room B, since you, C, changed the criteria and became an A.
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01-12-2014, 05:09 PM
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Senior CC Premier Member
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Join Date: Nov 2004
Location: SoCal,
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My son is math and Econ at UCLA. When I bring him a tough one (for me), I get the "One scoop chocolate, One scoop of vanilla...Don't waste my time!"
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All that's stopping you now Son, is blind-raging fear.......
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01-12-2014, 05:53 PM
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Senior CC Premier Member
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Join Date: Nov 2004
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Quote:
Originally Posted by Car Nut
Sounds like you need to go straight to your room B, since you, C, changed the criteria and became an A.
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C has no bearing on the question, best I can tell and based on the original question. C could be on the moon. AB could move from here to infinity and still be a straight line. My 2c. 
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All that's stopping you now Son, is blind-raging fear.......
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01-12-2014, 05:57 PM
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Half-Ass Member
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Join Date: Jun 2005
Cobra Make, Engine: ERA #732, 428FE (447 CID), TKO600, Solid Flat Tappet Cam, Tons of Aluminum
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Quote:
Originally Posted by Bernica
AB could move from here to infinity and still be a straight line. My 2c. |
Ooooh, you're close.... The real answer will depend on whether you take the view that parallel lines meet at infinity. |
01-12-2014, 06:24 PM
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Senior CC Premier Member
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Join Date: Nov 2004
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Did not pick up on parallel lines anywhere. Only one line. You got dat double vision goin' again Patrick?
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All that's stopping you now Son, is blind-raging fear.......
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