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  #81 (permalink)  
Old 01-14-2014, 09:12 PM
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BTW, Three Peeks had it right from the git-go ...

(120/146) x 1/8 = .103"
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  #82 (permalink)  
Old 01-17-2014, 05:33 PM
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You guys are amazing.

Thanks.
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  #83 (permalink)  
Old 01-17-2014, 05:45 PM
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That was a fun trip! Thanks for putting up with me!
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Old 01-18-2014, 12:41 PM
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Quote:
Originally Posted by AL427SBF View Post
A'
.......................................B'

A---------- ----------------B---------------------------------------C


Tangent (theta) = (opposite/adjacent) = (1/8")/146" = .000856
Arctan .000856 = 0.000855999791 rad

Tan (0.000855999791 rad) = Z/120"
Z = Tan (0.000855999791 rad) x 120"
Z = 0.000856 x 120"
Z = .103" (rounded)
So I guess you're assuming that the line ABC runs vertically, not horizontally as your diagram shows changing the movement of B to up not left. Right?
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  #85 (permalink)  
Old 01-18-2014, 09:03 PM
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I can't believe I just wasted about 30 minutes of my life and didn't learn a friggin' thing!
This definitely calls for another beer!
Ralph
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Old 01-18-2014, 09:45 PM
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I am still stuck on my "axis" and rotation deal. Axis being the variable, I think. But I still think if I move right or left, Joe (Mike) moves same direction as I did (my right to his right) off the axis of Patrick.
Sorry for the dumb-ass answer, but my level of competence is no match.
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Old 01-19-2014, 12:18 PM
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Ralphy, an equasion would be nice. That I could caculate for any distance to C.

Ralph, I did not think you needed any excuse for a beer.
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Old 01-19-2014, 12:56 PM
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Mike, I have the equations you are looking for. They're $200 each.
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