02-20-2004, 07:59 PM
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CC Member
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Join Date: Aug 2002
Location: Dalton,
GA
Cobra Make, Engine: West Coast 460, Performer Cam & Intake, Edelbrock 750cfm Carb
Posts: 256
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Not Ranked
Hey Chet,
I've spent some time (still not solved. I now suspect a weak battery.) problem with my system and a few gracious people from this site sent me schematics and I'll offer what I know based on an assumption that you have an external regulator and that the idiot light with resistor is wired to the "I" lead on the regulator.
First, the voltage won't drop when the battery is charged because you are measuring the voltgae across both the battery and the alternator at the same time. Essentially they are equal and the alternator won't send any more current to the battery once it's charged because there is no more volatge DIFFERENCE between the two. This is Good.
Afar as the light goes, it's actually in the start circuit. Turn the key on to get the motor turning and voltage will return back to the regulator on the "S" lead, a relay will trip, or transsistor turn on and voltage will shunt around the idiot light circuit and the light goes out. Notice the light comes on when you turn the key on And stays on until you get the engine running. If the alternator fails, no juice to the regulator via the "S" lead , relay or transistor off and current from the battery now flows through the light letting you know something's wrong. As far as the resistor goes, my guess is it is there to get the regulator up and running when you first start the car should the light bulb be burned out. If you didn't have voltage on that lead at start up, the voltage regulator would not give the initial shot of field voltage to the alternator and it would never send a return voltage on the "S" lead.
There are varations to this of course but hopefully I haven't made a really simple thing sound to complicated. (Yes I Have - lol) - The Wiz
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"Nobody gets to see the Wizard. Not Nobody. Not Nohow.
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